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Kinematik, freier Fall

Alles zum Thema Statik, Kinematik & Dynamik.

Kinematik, freier Fall

Beitragvon dianosch am So 1. Dez 2013, 19:29

Hey Leute,
ich muss für Mechanik einen Beleg machen und komme mit dieser Aufgabe absolut nicht klar:

Zur Simulation schwereloser Zustände werden
Vakuum-Fallschacht-Anlagen benutzt. Ein solcher
Schacht habe die Tiefe l = 200m. Diese sei in die
Bereiche I und II unterteilt.
Im Bereich I erfolgt die Simulation, da sich der Versuchskörper
hier im freien Fall befindet, während
im Bereich II der Versuchskörper mit der Beschleunigung
aII(x) abgebremst wird.
Welche maximale Versuchszeit t1 und welche Versuchsstrecke
x1 stehen zur Verfügung, wenn der
Versuchskörper das Ende des Bereiches 2 mit v = 0
erreichen soll?
gegeben:
• Bereich 1: t element [0; t1], x element [0; x1], aI = g = 9;81 m/s2 = const.
*Bereich 2: t element [t1;t2], x element [x1;x2], aII(x) = (x-x1)/(x1-x2) * 350 m/s2


Versteht das jemand, kann mir irgendwer helfen? Ich weiß noch nicht mal im entferntesten wie ich da rangehen soll!
Bitte helft mir!
dianosch
 
Beiträge: 1
Registriert: So 1. Dez 2013, 18:52

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